| tune.control {e1071} | R Documentation |
Creates an object of class tune.control to be used with
the tune function, containing various control parameters.
tune.control(random = FALSE, nrepeat = 1, repeat.aggregate = min,
sampling = c("cross", "fix", "bootstrap"), sampling.aggregate = mean,
cross = 10, fix = 2/3, nboot = 10, boot.size = 9/10, best.model = TRUE,
performances = TRUE)
random |
if an integer value is specified, random
parameter vectors are drawn from the parameter space. |
nrepeat |
specifies how often training shall be repeated. |
repeat.aggregate |
function for aggregating the repeated training results. |
sampling |
sampling scheme. If sampling = "cross", a
cross-times cross validation is performed. If sampling
= "boot", nboot training sets of size boot.size (part)
are sampled from the supplied data. If sampling
= "fix", a single split into training/validation set is
used, the training set containing a fix part of the supplied
data. Note that a separate validation set can be supplied via
validation.x and validation.y. It is only used for
sampling = "boot" and sampling = "fix"; in the latter
case, fix is set to 1. |
sampling.aggregate |
function for aggregating the training results on the generated training samples. |
cross |
number of partitions for cross-validation. |
fix |
part of the data used for training in fixed sampling. |
nboot |
number of bootstrap replications. |
bthe supplied
datting function
| |
subset |
An index vector specifying the cases to be used in the training sample. (NOTE: If given, this argument must be named.) |
na.action |
A function to specify the action to be taken if NAs are
found. The default action is na.omit, which leads to rejection of cases
with missing values on any required variable. An alternative
is na.fail, which causes an error if NA cases
are found. (NOTE: If given, this argument must be named.) |
For multiclass-classification with k levels, k>2, libsvm uses the
‘one-against-one’-approach, in which k(k-1)/2 binary classifiers are
trained; the appropriate class is found by a voting scheme.